y^2(3y-4)+7(3y-4)=0

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Solution for y^2(3y-4)+7(3y-4)=0 equation: 


Simplifying
y2(3y + -4) + 7(3y + -4) = 0

Reorder the terms:
y2(-4 + 3y) + 7(3y + -4) = 0
(-4 * y2 + 3y * y2) + 7(3y + -4) = 0
(-4y2 + 3y3) + 7(3y + -4) = 0

Reorder the terms:
-4y2 + 3y3 + 7(-4 + 3y) = 0
-4y2 + 3y3 + (-4 * 7 + 3y * 7) = 0
-4y2 + 3y3 + (-28 + 21y) = 0

Reorder the terms:
-28 + 21y + -4y2 + 3y3 = 0

Solving
-28 + 21y + -4y2 + 3y3 = 0

Solving for variable 'y'.

The solution to this equation could not be determined.

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